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Chemistry · 2025

JEE Main · 2 April 2025, Shift 2 · Q56

Reactant A converts to product D through the given mechanism (with the net evolution of heat): A → B, slow; Δ H =+ ve; B → C, fast; Δ H =- ve; C → D,…

Reactant A converts to product D through the given mechanism (with the net evolution of heat) : $$\begin{array}{lll} \text { A } \rightarrow \text { B } & \text { slow; } & \Delta \mathrm{H}=+ \text { ve } \\ \text { B } \rightarrow \mathrm{C} & \text { fast } ; & \Delta \mathrm{H}=-\mathrm{ve} \\ \mathrm{C} \rightarrow \mathrm{D} & \text { fast } ; & \Delta \mathrm{H}=-\mathrm{ve} \end{array} $$ Which of the following represents the above reaction mechanism ?
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JEE Main 2025 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.