SolveItJEE Main
Chemistry · 2024

JEE Main · 30 January 2024, Shift 2 · Q85

NO_2 required for a reaction is produced by decomposition of N_2 O_5 in CCl_4 as by equation 2 N_2 O_5( g ) → 4 NO_2( g ) + O_2( g ) The initial…

$\displaystyle \mathrm{NO}_2$ required for a reaction is produced by decomposition of $\displaystyle \mathrm{N}_2 \mathrm{O}_5$ in $\displaystyle \mathrm{CCl}_4$ as by equation $$2 \mathrm{~N}_2 \mathrm{O}_{5(\mathrm{~g})} \rightarrow 4 \mathrm{NO}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})} $$ The initial concetration. of $\displaystyle \mathrm{N}_2 \mathrm{O}_5$ is $\displaystyle 3 \mathrm{~mol} \mathrm{~L}^{-1}$ and it is $\displaystyle 2.75 \mathrm{~mol} \mathrm{~L}^{-1}$ after $\displaystyle 30$ minutes.The rate of formation of $\displaystyle \mathrm{NO}_2$ is $\displaystyle \mathrm{x} \times 10^{-3} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~min}^{-1}$, value of x is $\displaystyle \_\_\_\_$. (nearest integer)
ShareWhatsAppTelegram

More from Chemical Kinetics

JEE Main 2024 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.