Chemistry · 2015
JEE Main · 11 April 2015, Shift 1 · Q31
A +2 B +3 C ⇌ AB_2 C_3 Reaction of 6.0 g of A, 6.0 × 10^23 atoms of B, and 0.036 mol of C yields 4.8 g of compound AB_2 C_3. If the atomic mass of A…
$$\mathrm{A}+2 \mathrm{~B}+3 \mathrm{C} \rightleftharpoons \mathrm{AB}_2 \mathrm{C}_3
$$
Reaction of $\displaystyle 6.0$ g of $\displaystyle \mathrm{A}, 6.0 \times 10^{23}$ atoms of B, and $\displaystyle 0.036$ mol of C yields $\displaystyle 4.8$ g of compound $\displaystyle \mathrm{AB}_2 \mathrm{C}_3$. If the atomic mass of A and C are $\displaystyle 60$ and $\displaystyle 80$ amu, respectively, the atomic mass of B is (Avogadro no. $\displaystyle =6 \times 10^{23}$ ) :
Official answer
(3)
$\displaystyle 50$ amu
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JEE Main 2015 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.