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Chemistry · 2017

JEE Main 2017 · 2017-04-02 Offline · Q32

1 gram of a carbonate ( M_2 CO_3 ) on treatment with excess HCl produces 0.01186 mole of CO_2. The molar mass of M_2 CO_3 in g mol^-1 is:

$\displaystyle 1$ gram of a carbonate ( $\displaystyle \mathrm{M}_2 \mathrm{CO}_3$ ) on treatment with excess HCl produces $\displaystyle 0.01186$ mole of $\displaystyle \mathrm{CO}_2$. The molar mass of $\displaystyle \mathrm{M}_2 \mathrm{CO}_3$ in $\displaystyle \mathrm{g} \mathrm{mol}^{-1}$ is :
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