2 SO_2( g )+ O_2( g ) → 2 SO_3( g ) The above reaction is carried out in a vessel starting with partial pressures P_SO_2 =250 m bar, P_O_2 =750 m bar…

$$2 \mathrm{SO}_2(\mathrm{~g})+\mathrm{O}_2(\mathrm{~g}) \rightarrow 2 \mathrm{SO}_3(\mathrm{~g}) $$ The above reaction is carried out in a vessel starting with partial pressures $\displaystyle \mathrm{P}_{\mathrm{SO}_2}=250 \mathrm{~m}$ bar, $\displaystyle \mathrm{P}_{\mathrm{O}_2}=750 \mathrm{~m}$ bar and $\displaystyle \mathrm{P}_{\mathrm{SO}_3}=0$ bar. When the reaction is complete, the total pressure in the reaction vessel is \_\_\_\_ m bar. (Round off to the Nearest Integer).