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JEE Main 2016 · 2016-04-03 Offline · Q31

At 300 K and 1 atm, 15 mL of a gaseous hydrocarbon requires 375 mL air containing 20 % O_2 by volume for complete combustion. After combustion the…

At $\displaystyle 300$ K and $\displaystyle 1$ atm, $\displaystyle 15$ mL of a gaseous hydrocarbon requires $\displaystyle 375$ mL air containing $\displaystyle 20 \% \mathrm{O}_2$ by volume for complete combustion. After combustion the gases occupy $\displaystyle 330$ mL . Assuming that the water formed is in liquid form and the volumes were measured at the same temperature and pressure, the formula of the hydrocarbon is :
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JEE Main 2016 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.