Chemistry · 2026
JEE Main · 5 April 2026, Shift 2 · Q57
One half cell in a voltaic cell is constructed by dipping silver rod in AgNO_3 solution of unknown concentration, other half cell is Zn rod dipped in…
One half cell in a voltaic cell is constructed by dipping silver rod in $\displaystyle \mathrm{AgNO}_3$ solution of unknown concentration, other half cell is Zn rod dipped in $\displaystyle 1$ molar solution of $\displaystyle \mathrm{ZnSO}_4$.
A voltage of $\displaystyle 1.60$ V is measured at $\displaystyle 298$ K for this cell. What is the concentration of $\displaystyle \mathrm{Ag}^{+}$ions used in terms of $\displaystyle \log x\left(x=\left[\mathrm{Ag}^{+}\right]\right)$?
$$\mathrm{E}_{\mathrm{Zn}^{2+} / \mathrm{Zn}}^{\ominus}=-0.76 \mathrm{~V}, \quad \mathrm{E}_{\mathrm{Ag}^{+} / \mathrm{Ag}}^{\ominus}=+0.80 \mathrm{~V}, \frac{2.303 \mathrm{RT}}{\mathrm{~F}}=0.059 \mathrm{~V}
$$
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle \frac{4}{5.9}$
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JEE Main 2026 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.