Chemistry · 2026
JEE Main · 5 April 2026, Shift 2 · Q74
At 298 K, the molar conductivity of x %( w / w ) MX solution (aqueous) is 123.5 S cm^2 mol^-1. The conductance of same solution is 1.9 × 10^-3 S. The…
At $\displaystyle 298$ K, the molar conductivity of $\displaystyle x \%(\mathrm{w} / \mathrm{w}) \mathrm{MX}$ solution (aqueous) is $\displaystyle 123.5 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$. The conductance of same solution is $\displaystyle 1.9 \times 10^{-3} \mathrm{~S}$. The value of $\displaystyle x$ is $\displaystyle \_\_\_\_$ $\displaystyle \times 10^{-2}$.
(Given : cell constant $\displaystyle =1.3 \mathrm{~cm}^{-1}$; molar mass of MX is $\displaystyle 75 \mathrm{~g} \mathrm{~mol}^{-1}$, density of aqueous solution of MX at $\displaystyle 298$ K is $\displaystyle 1.0 \mathrm{~g} \mathrm{~mL}^{-1}$ )
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JEE Main 2026 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.