Consider the following data. BaSO_4 is sparingly soluble in water. If the conductivity of the saturated BaSO_4 solution is x S cm^-1 then the…

Consider the following data.

Electrolyte	$\displaystyle \boldsymbol{\Lambda}^{\boldsymbol{\circ}}{ }_{\mathbf{m}} \boldsymbol{(} \mathbf{S ~ c m}^{\mathbf{2}} \mathbf{~ m o l}^{\boldsymbol{-} \mathbf{1}} \boldsymbol{)}$
$\displaystyle \mathrm{BaCl}_2$	$\displaystyle x_1$
$\displaystyle \mathrm{H}_2 \mathrm{SO}_4$	$\displaystyle x_2$
HCl	$\displaystyle x_3$

$\displaystyle \mathrm{BaSO}_4$ is sparingly soluble in water. If the conductivity of the saturated $\displaystyle \mathrm{BaSO}_4$ solution is $\displaystyle x \mathrm{~S} \mathrm{~cm}^{-1}$ then the solubility product of $\displaystyle \mathrm{BaSO}_4$ can be given as (Here $\displaystyle \Lambda_{\mathrm{m}}=\Lambda_{\mathrm{m}}^{\circ}$ )