Chemistry · 2026
JEE Main · 2 April 2026, Shift 1 · Q57
An electrochemical cell is constructed using half cells in the direction of spontaneous change Fe ( OH )_2( s )+2 e^- → Fe ( s )+2 OH^-( aq ),…
An electrochemical cell is constructed using half cells in the direction of spontaneous change
$$\begin{array}{ll}
\mathrm{Fe}(\mathrm{OH})_2(\mathrm{~s})+2 \mathrm{e}^{-} \rightarrow \mathrm{Fe}(\mathrm{~s})+2 \mathrm{OH}^{-}(\mathrm{aq}) & \mathrm{E}^\theta=-0.88 \mathrm{~V} \\
\text { and } \mathrm{AgBr}(\mathrm{~s})+\mathrm{e}^{-} \rightarrow \mathrm{Ag}(\mathrm{~s})+\mathrm{Br}^{-}(\mathrm{aq}) & \mathrm{E}^\theta=+0.07 \mathrm{~V}
\end{array}
$$
Which of the following option is correct ?
Official answer
From NTA’s final answer key for this paper.
(1)
Overall reaction $\displaystyle \mathrm{Fe}(\mathrm{s})+2 \mathrm{OH}^{-}(\mathrm{aq})+2 \mathrm{AgBr}(\mathrm{s}) \rightleftharpoons \mathrm{Fe}(\mathrm{OH})_2(\mathrm{~s})+2 \mathrm{Ag}(\mathrm{s})+2 \mathrm{Br}^{-}(\mathrm{aq})$
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JEE Main 2026 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.