Chemistry · 2019
JEE Main · 9 January 2019, Shift 2 · Q58
If the standard electrode potential for a cell is 2 V at 300 K, the equilibrium constant (K) for the reaction Zn ( s )+ Cu^2+( aq ) ⇌ Zn^2+( aq )+ Cu…
If the standard electrode potential for a cell is $\displaystyle 2$ V at $\displaystyle 300$ K , the equilibrium constant (K) for the reaction
$$\mathrm{Zn}(\mathrm{~s})+\mathrm{Cu}^{2+}(\mathrm{aq}) \rightleftharpoons \mathrm{Zn}^{2+}(\mathrm{aq})+\mathrm{Cu}(\mathrm{~s})
$$
at $\displaystyle 300$ K is approximately
$$\left(\mathrm{R}=8 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}, \mathrm{~F}=96000 \mathrm{C} \mathrm{~mol}^{-1}\right)
$$
Official answer
(4)
$\displaystyle e^{160}$
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JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.