Given the equilibrium constant: K_C of the reaction: Cu ( s )+2 Ag^+( aq ) → Cu^2+( aq )+2 Ag ( s ) is 10 × 10^15, calculate the E_cell^θ of this…

Given the equilibrium constant : $\displaystyle \mathrm{K}_{\mathrm{C}}$ of the reaction : $\displaystyle \mathrm{Cu}(\mathrm{s})+2 \mathrm{Ag}^{+}(\mathrm{aq}) \rightarrow \mathrm{Cu}^{2+}(\mathrm{aq})+2 \mathrm{Ag}(\mathrm{s})$ is $\displaystyle 10 \times 10^{15}$, calculate the $\displaystyle \mathrm{E}_{\text {cell }}^\theta$ of this reaction at $\displaystyle 298$ K $$\left[2.303 \frac{\mathrm{RT}}{\mathrm{~F}} \text { at } 298 \mathrm{~K}=0.059 \mathrm{~V}\right] $$