Chemistry · 2019
JEE Main · 10 January 2019, Shift 1 · Q58
Consider the following reduction processes: Zn^2++2 e^- → Zn ( s ); E^°=-0.76 V; Ca^2++2 e^- → Ca ( s ); E^°=-2.87 V; Mg^2++2 e^- → Mg ( s );…
Consider the following reduction processes :
$$\begin{aligned}
& \mathrm{Zn}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Zn}(\mathrm{~s}) ; \mathrm{E}^{\circ}=-0.76 \mathrm{~V} \\
& \mathrm{Ca}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Ca}(\mathrm{~s}) ; \mathrm{E}^{\circ}=-2.87 \mathrm{~V} \\
& \mathrm{Mg}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Mg}(\mathrm{~s}) ; \mathrm{E}^{\circ}=-2.36 \mathrm{~V} \\
& \mathrm{Ni}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Ni}(\mathrm{~s}) ; \mathrm{E}^{\circ}=-0.25 \mathrm{~V}
\end{aligned}
$$
The reducing power of the metals increases in the order:
Official answer
(3)
$\displaystyle \mathrm{Ni}<\mathrm{Zn}<\mathrm{Mg}<\mathrm{Ca}$
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JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.