Chemistry · 2019
JEE Main · 12 January 2019, Shift 2 · Q55
Given: (i) C (graphite) + O_2( g ) → CO_2( g ); Δ rH^ =x kJ mol^-1 (ii) C (graphite) +1/2 O_2( g ) → CO_2( g ); Δ rH^ =y kJ mol^-1 (iii) CO ( g )+1/2…
Given :
(i)
$$\begin{aligned}
& \mathrm{C} \text { (graphite) }+\mathrm{O}_2(\mathrm{~g}) \rightarrow \mathrm{CO}_2(\mathrm{~g}) ;
& \Delta \mathrm{rH}^{\ominus}=x \mathrm{~kJ} \mathrm{~mol}^{-$\displaystyle 1$}
\end{aligned}
$$(ii)
$$
\begin{aligned}
& \mathrm{C} \text { (graphite) }+\frac{1}{2} \mathrm{O}_2(\mathrm{~g}) \rightarrow \mathrm{CO}_2(\mathrm{~g}) ;
& \Delta \mathrm{rH}^{\ominus}=y \mathrm{~kJ} \mathrm{~mol}^{-$\displaystyle 1$}
\end{aligned}
$$(iii)
$$\begin{aligned}
& \mathrm{CO}(\mathrm{~g})+\frac{1}{2} \mathrm{O}_2(\mathrm{~g}) \rightarrow \mathrm{CO}_2(\mathrm{~g}) ;
& \Delta \mathrm{rH}^{\ominus}=z \mathrm{~kJ} \mathrm{~mol}^{-$\displaystyle 1$}
\end{aligned}
$$Based on the above thermochemical equations, find out which one of the following algebraic relationships is correct?
Official answer
(1)
$\displaystyle x=y+z$
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JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.