Chemistry · 2018
JEE Main · 15 April 2018, Shift 2 · Q35
Given (i) 2 Fe_2 O_3( s ) → 4 Fe ( s )+3 O_2( g ); Δ_r G^°=+1487.0 kJ mol^-1 (ii) 2 CO ( g )+ O_2( g ) → 2 CO_2( g ); Δ_r G^°=-514.4 kJ mol^-1 Free…
Given
(i)
$$\begin{aligned}
& $\displaystyle 2$ \mathrm{Fe}_2 \mathrm{O}_3(\mathrm{~s}) \rightarrow $\displaystyle 4$ \mathrm{Fe}(\mathrm{~s})+$\displaystyle 3$ \mathrm{O}_2(\mathrm{~g}) ;
& \Delta_{\mathrm{r}} \mathrm{G}^{\circ}=+$\displaystyle 1487.0$ \mathrm{~kJ} \mathrm{~mol}^{-$\displaystyle 1$}
\end{aligned}
$$(ii)
$$
\begin{aligned}
& $\displaystyle 2$ \mathrm{CO}(\mathrm{~g})+\mathrm{O}_2(\mathrm{~g}) \rightarrow $\displaystyle 2$ \mathrm{CO}_2(\mathrm{~g}) ;
& \Delta_{\mathrm{r}} \mathrm{G}^{\circ}=-$\displaystyle 514.4$ \mathrm{~kJ} \mathrm{~mol}^{-$\displaystyle 1$}
\end{aligned}
$$Free energy change, $\displaystyle \Delta_{\mathrm{r}} G^{\circ}$ for the reaction $\displaystyle 2 \mathrm{Fe}_2 \mathrm{O}_3(\mathrm{~s})+6 \mathrm{CO}(\mathrm{g}) \rightarrow 4 \mathrm{Fe}(\mathrm{s})+6 \mathrm{CO}_2(\mathrm{~g})$ will be :
Official answer
(2)
$\displaystyle -56.2 \mathrm{~kJ} \mathrm{~mol}^{-1}$
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JEE Main 2018 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.