For complete combustion of methanol CH_3 OH ( l )+3/2 O_2( g ) → CO_2( g )+2 H_2 O ( l ) the amount of heat produced as measured by bomb calorimeter…

For complete combustion of methanol $$\mathrm{CH}_3 \mathrm{OH}(\mathrm{l})+\frac{3}{2} \mathrm{O}_2(\mathrm{~g}) \rightarrow \mathrm{CO}_2(\mathrm{~g})+2 \mathrm{H}_2 \mathrm{O}(\mathrm{l}) $$ the amount of heat produced as measured by bomb calorimeter is $\displaystyle 726 \mathrm{~kJ} \mathrm{~mol}^{-1}$ at $\displaystyle 27$°C. The enthalpy of combustion for the reaction is $\displaystyle -x \mathrm{~kJ} \mathrm{~mol}^{-1}$, where $\displaystyle x$ is \_\_\_\_. (Nearest integer) (Given : $\displaystyle \mathrm{R}=8.3 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}$ )