Chemistry · 2024
JEE Main · 4 April 2024, Shift 1 · Q85
Consider the following transformation involving first order elementary reaction in each step at constant temperature as shown below. A+B [ Step 3]…
Consider the following transformation involving first order elementary reaction in each step at constant temperature as shown below.
$$A+B \xrightleftharpoons[\text { Step } 3]{\text { Step 1 }} C \xrightarrow{\text { Step 2 }} P
$$
Some details of the above reactions are listed below.
If the overall rate constant of the above transformation (k) is given as $\displaystyle \mathrm{k}=\frac{\mathrm{k}_1 \mathrm{k}_2}{\mathrm{k}_3}$ and the overall activation energy $\displaystyle \left(\mathrm{E}_{\mathrm{a}}\right)$ is $\displaystyle 400 \mathrm{~kJ} \mathrm{~mol}^{-1}$, then the value of $\displaystyle \mathrm{Ea}_3$ is $\displaystyle \_\_\_\_$ $\displaystyle \mathrm{kJ} \mathrm{mol}^{-1}$ (nearest integer)
| Step | Rate constant $\displaystyle \left(\mathrm{sec}^{-1}\right)$ | Activation energy ( $\displaystyle \mathrm{kJ} \mathrm{mol}^{-1}$ ) |
| $\displaystyle 1$ | $\displaystyle \mathrm{k}_1$ | $\displaystyle 300$ |
| $\displaystyle 2$ | $\displaystyle \mathrm{k}_2$ | $\displaystyle 200$ |
| $\displaystyle 3$ | $\displaystyle \mathrm{k}_3$ | $\displaystyle \mathrm{Ea}_3$ |
Official answer
From NTA’s final answer key for this paper.
100
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JEE Main 2024 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.