Consider the following reaction A+B → C The time taken for A to become 1 / 4^th of its initial concentration is twice the time taken to become 1 / 2…

Consider the following reaction $$A+B \rightarrow C $$The time taken for A to become $\displaystyle 1 / 4^{\text {th }}$ of its initial concentration is twice the time taken to become $\displaystyle 1 / 2$ of the same. Also, when the change of concentration of $\displaystyle B$ is plotted against time, the resulting graph gives a straight line with a negative slope and a positive intercept on the concentration axis.The overall order of the reaction is $\displaystyle \_\_\_\_$.