Chemistry · 2023
JEE Main · 29 January 2023, Shift 1 · Q53
Consider the following reaction approaching equilibrium at 27^° C and 1 atm pressure A + B k_r=10^2 k_f=10^3 ⇌ C+D The standard Gibb's energy change…
Consider the following reaction approaching equilibrium at $\displaystyle 27^{\circ} \mathrm{C}$ and $\displaystyle 1$ atm pressure
$$\mathrm{A}+\mathrm{B} \underset{k_r=10^2}{\stackrel{\mathrm{k}_f=10^3}{\rightleftharpoons}} C+D
$$
The standard Gibb's energy change ( $\displaystyle \Delta_{\mathrm{r}} \mathrm{G}^\theta$ ) at $\displaystyle 27^{\circ} \mathrm{C}$ is ( - ) $\displaystyle \_\_\_\_$ $\displaystyle \mathrm{kJ} \mathrm{mol}^{-1}$
(Nearest integer).
(Given: $\displaystyle \mathrm{R}=8.3 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$ and $\displaystyle \ln 10=2.3$ )
Official answer
From NTA’s final answer key for this paper.
6
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JEE Main 2023 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.