Consider the cell Pt_( s ) | H_2( g, 1 atm )| H^+( aq, 1 M ) ∥ Fe^3+( aq ), Fe^2+( aq ) ∣ Pt ( s ) When the potential of the cell is 0.712 V at 298…

Consider the cell $\displaystyle \mathrm{Pt}_{(\mathrm{s})}\left|\mathrm{H}_2(\mathrm{~g}, 1 \mathrm{~atm})\right| \mathrm{H}^{+}(\mathrm{aq}, 1 \mathrm{M}) \| \mathrm{Fe}^{3+}(\mathrm{aq}), \mathrm{Fe}^{2+}(\mathrm{aq}) \mid \mathrm{Pt}(\mathrm{s})$ When the potential of the cell is $\displaystyle 0.712$ V at $\displaystyle 298$ K, the ratio $\displaystyle \left[\mathrm{Fe}^{2+}\right] /\left[\mathrm{Fe}^{3+}\right]$ is $\displaystyle \_\_\_\_$. (Nearest integer) Given : $\displaystyle \mathrm{Fe}^{3+}+\mathrm{e}^{-} \rightleftharpoons \mathrm{Fe}^{2+}, \mathrm{E}^\theta \mathrm{Fe}^{3+}, \mathrm{Fe}^{2+} \mid \mathrm{Pt}=0.771$ $$\frac{2.303 \mathrm{RT}}{\mathrm{~F}}=0.06 \mathrm{~V} $$