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Chemistry · 2024

JEE Main · 1 February 2024, Shift 1 · Q85

The potential for the given half cell at 298 K is ( - ) ____ × 10^-2 V. 2 H_( aq )^++2 e^- → H_2( g ); [ H^+]=1 M, P_H_2 =2 atm (Given: 2.303 RT / F…

The potential for the given half cell at $\displaystyle 298$ K is ( - ) $\displaystyle \_\_\_\_$ $\displaystyle \times 10^{-2} \mathrm{~V}$. $$\begin{aligned} & 2 \mathrm{H}_{(\mathrm{aq})}^{+}+2 \mathrm{e}^{-} \longrightarrow \mathrm{H}_2(\mathrm{~g}) \\ & {\left[\mathrm{H}^{+}\right]=1 \mathrm{M}, \mathrm{P}_{\mathrm{H}_2}=2 \mathrm{~atm}} \end{aligned} $$ (Given : $\displaystyle 2.303 \mathrm{RT} / \mathrm{F}=0.06 \mathrm{~V}, \log 2=0.3$ )
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JEE Main 2024 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.