The equilibrium constant for the reaction Zn ( s )+ Sn^2+( aq ) ⇌ Zn^2+( aq )+ Sn ( s ) is 1 × 10^20 at 298 K. The magnitude of standard electrode…

The equilibrium constant for the reaction $\displaystyle \mathrm{Zn}(\mathrm{s})+\mathrm{Sn}^{2+}(\mathrm{aq}) \rightleftharpoons \mathrm{Zn}^{2+}(\mathrm{aq})+\mathrm{Sn}(\mathrm{s})$ is $\displaystyle 1 \times 10^{20}$ at $\displaystyle 298$ K . The magnitude of standard electrode potential of $\displaystyle \mathrm{Sn} / \mathrm{Sn}^{2+}$ if $\displaystyle \mathrm{E}_{\mathrm{Zn}^{2+} / \mathrm{Zn}}^{\theta}=-0.76 \mathrm{~V}$ is $\displaystyle \_\_\_\_$ $\displaystyle \times 10^{-2} \mathrm{~V}$. (Nearest integer). Given : $\displaystyle \frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.059 \mathrm{~V}$