The electrode potential of the following half cell at 298 K X | X^2+(0.001 M ) ∥ Y^2+(0.01 M )| Y is ____ × 10^-2 V (Nearest integer). Given: E_X^2+…

The electrode potential of the following half cell at $\displaystyle 298$ K $\displaystyle \mathrm{X}\left|\mathrm{X}^{2+}(0.001 \mathrm{M}) \| \mathrm{Y}^{2+}(0.01 \mathrm{M})\right| \mathrm{Y}$ is $\displaystyle \_\_\_\_$ $\displaystyle \times 10^{-2} \mathrm{~V}$ (Nearest integer).Given: $\displaystyle \mathrm{E}_{\mathrm{X}^{2+} \mid \mathrm{X}}^{\circ}=-2.36 \mathrm{~V}$ $$\begin{aligned} & \mathrm{E}_{\mathrm{Y}^{2+} \mid \mathrm{Y}}^{\circ}=+0.36 \mathrm{~V} \\ & \frac{2.303 \mathrm{RT}}{\mathrm{~F}}=0.06 \mathrm{~V} \end{aligned} $$