Chemistry · 2018
JEE Main · 16 April 2018, Shift 1 · Q39
At 320 K, a gas A_2 is 20 % dissociated to A(g). The standard free energy change at 320 K and 1 atm in J mol^-1 is approximately: ( R =8.314 JK^-1…
At $\displaystyle 320$ K , a gas $\displaystyle \mathrm{A}_2$ is $\displaystyle 20 \%$ dissociated to A(g). The standard free energy change at $\displaystyle 320$ K and $\displaystyle 1$ atm in $\displaystyle \mathrm{J} \mathrm{mol}^{-1}$ is approximately : $\displaystyle \left(\mathrm{R}=8.314 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\right.$; $\displaystyle \ln 2=0.693 ; \ln 3=1.098)$
Official answer
(1)
$\displaystyle 4763$
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JEE Main 2018 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.