A_2+ B_2 → 2 AB. Δ H_f^0=-200 kJ mol^-1 AB, A_2 and B_2 are diatomic molecules. If the bond enthalpies of A_2, B_2 and AB are in the ratio 1:0.5:1,…

$\displaystyle \mathrm{A}_2+\mathrm{B}_2 \rightarrow 2 \mathrm{AB}. \Delta H_f^0=-200 \mathrm{~kJ} \mathrm{~mol}^{-1}$ $\displaystyle \mathrm{AB}, \mathrm{A}_2$ and $\displaystyle \mathrm{B}_2$ are diatomic molecules. If the bond enthalpies of $\displaystyle \mathrm{A}_2, \mathrm{~B}_2$ and AB are in the ratio $\displaystyle 1$:$\displaystyle 0.5$:$\displaystyle 1$, then the bond enthalpy of $\displaystyle \mathrm{A}_2$ is $\displaystyle \_\_\_\_$ $\displaystyle \mathrm{kJ} \mathrm{mol}^{-1}$ (Nearest integer)