Chemistry · 2018
JEE Main · 15 April 2018, Shift 1 · Q40
An ideal gas undergoes a cyclic process as shown in Figure. Δ U_BC =-5 kJ mol^-1, q_AB =2 kJ mol^-1 W_AB =-5 kJ mol^-1, W_CA =3 kJ mol^-1 Heat…
An ideal gas undergoes a cyclic process as shown in Figure.
$\displaystyle \Delta \mathrm{U}_{\mathrm{BC}}=-5 \mathrm{~kJ} \mathrm{~mol}^{-1}, \mathrm{q}_{\mathrm{AB}}=2 \mathrm{~kJ} \mathrm{~mol}^{-1}$ $\displaystyle \mathrm{W}_{\mathrm{AB}}=-5 \mathrm{~kJ} \mathrm{~mol}^{-1}, \mathrm{~W}_{\mathrm{CA}}=3 \mathrm{~kJ} \mathrm{~mol}^{-1}$
Heat absorbed by the system during process CA is :
$\displaystyle \Delta \mathrm{U}_{\mathrm{BC}}=-5 \mathrm{~kJ} \mathrm{~mol}^{-1}, \mathrm{q}_{\mathrm{AB}}=2 \mathrm{~kJ} \mathrm{~mol}^{-1}$ $\displaystyle \mathrm{W}_{\mathrm{AB}}=-5 \mathrm{~kJ} \mathrm{~mol}^{-1}, \mathrm{~W}_{\mathrm{CA}}=3 \mathrm{~kJ} \mathrm{~mol}^{-1}$
Heat absorbed by the system during process CA is :Official answer
(2)
$\displaystyle +5 \mathrm{~kJ} \mathrm{~mol}^{-1}$
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JEE Main 2018 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.