Chemistry · 2023
JEE Main · 25 January 2023, Shift 1 · Q53
An athlete is given 100 g of glucose ( C_6 H_12 O_6) for energy. This is equivalent to 1800 kJ of energy. The 50 % of this energy gained is utilized…
An athlete is given $\displaystyle 100$ g of glucose $\displaystyle \left(\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6\right)$ for energy. This is equivalent to $\displaystyle 1800$ kJ of energy. The $\displaystyle 50 \%$ of this energy gained is utilized by the athlete for sports activities at the event. In order to avoid storage of energy, the weight of extra water he would need to perspire is $\displaystyle \_\_\_\_$ g (Nearest integer)Assume that there is no other way of consuming stored energy.
Given : The enthalpy of evaporation of water is $\displaystyle 45 \mathrm{~kJ} \mathrm{~mol}^{-1}$
Molar mass of $\displaystyle \mathrm{C}, \mathrm{H} \& \mathrm{O}$ are $\displaystyle 12,1$ and $\displaystyle 16 \mathrm{~g} \mathrm{~mol}^{-1}$.
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From NTA’s final answer key for this paper.
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JEE Main 2023 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.