Chemistry · 2019
JEE Main · 8 April 2019, Shift 2 · Q55
5 moles of an ideal gas at 100 K are allowed to undergo reversible compression till its temperature becomes 200 K. If C_V =28 J K^-1 mol^-1,…
$\displaystyle 5$ moles of an ideal gas at $\displaystyle 100$ K are allowed to undergo reversible compression till its temperature becomes $\displaystyle 200$ K. If $\displaystyle \mathrm{C}_{\mathrm{V}}=28 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$, calculate $\displaystyle \Delta \mathrm{U}$ and $\displaystyle \Delta \mathrm{pV}$ for this process. $\displaystyle \left(\mathrm{R}=8.0 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right)$
Official answer
(3)
$\displaystyle \Delta \mathrm{U}=14 \mathrm{~kJ} ; \Delta(\mathrm{pV})=4 \mathrm{~kJ}$
More from Chemical Thermodynamics
- For water at 100^° C and 1 bar, Δ_vap H-Δ_vap U= \ \ \ \ × 10^2 J mol^-1. (Round off to the Nearest Integer) [. Use:.R=8.31 J mol^-1 K^-1] [Assume…2021
- 0 g of NH_3 completely vapourises at -33.42^° C and 1 bar pressure and the enthalpy change in the process is 23.4 kJ mol^-1. The enthalpy change for…2022
- Consider the reaction 2 H_2 S( g)+3 O_2( g) → 2 H_2 O(l)+2 SO_2( g) The magnitude of enthalpy change for the reaction in kJ mol^-1 is ____. (Nearest…2026
- A sample of n-octane (1.14 g) was completely burnt in excess of oxygen in a bomb calorimeter, whose heat capacity is 5 kJ K^-1. As a result of…2025
- The gas phase reaction 2 A( g) ⇌ A_2( g) at 400 K has Δ G^°=+25.2 kJ mol^-1. The equilibrium constant K_C for this reaction is \ \ \ \ × 10^-2.…2021
- For the reaction A_(g) → B_(g), the value of the equilibrium constant at 300 K and 1 atm is equal to 100.0. The value of Δ_r G for the reaction at…2021
- One mole of an ideal monoatomic gas is subjected to changes as shown in the graph. The magnitude of the work done (by the system or on the system) is…2023
- 1 mole of ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27^° C. The work done is 3 kJ mol^-1. The final…2023
JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.