CBSE 2024 · Region 1 · Set 3 · Q4 · 1 mark
Two charged particles, $\displaystyle P$ and $\displaystyle Q$, each having charge $\displaystyle q$ but of masses $\displaystyle \mathrm{m}_{1}$ and $\displaystyle \mathrm{m}_{2}$, are accelerated through the same potential difference V . They enter a region of magnetic field $\displaystyle \overrightarrow{\mathrm{B}}(\perp \overrightarrow{\mathrm{v}})$ and describe the circular paths of radii $\displaystyle \mathrm{a}$ and $\displaystyle \mathrm{b}$ respectively. Then $\displaystyle \left(\frac{\mathrm{m}_{1}}{\mathrm{~m}_{2}}\right)$ is equal to :
Official answer
From CBSE’s own marking scheme for this paper.
(C)
$\displaystyle \left(\frac{\mathrm{a}}{\mathrm{b}}\right)^{2}$
Moving Charges and MagnetismMotion in a Magnetic FieldApplymcqmedium
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CBSE Class 12 Physics past-paper question from the 2024board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.