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Physics · 2024 · 3 marks
Electrostatic Potential and CapacitancePotential Energy of a System of Charges3 marksApplyshort answer
CBSE 2024 · Region 1 · Set 2 · Q22
Three point charges Q_1, Q_2 and Q_3 are located in x - y plane at points (- d, 0),(0,0) and ( d, 0) respectively. Q_1 and Q_3 are identical and Q_2…
Three point charges $\displaystyle \mathrm{Q}_{1}, \mathrm{Q}_{2}$ and $\displaystyle \mathrm{Q}_{3}$ are located in $\displaystyle \mathrm{x}-\mathrm{y}$ plane at points $\displaystyle (-\mathrm{d}, 0),(0,0)$ and $\displaystyle (\mathrm{d}, 0)$ respectively. $\displaystyle \mathrm{Q}_{1}$ and $\displaystyle \mathrm{Q}_{3}$ are identical and $\displaystyle \mathrm{Q}_{2}$ is positive. What will be the nature and value of $\displaystyle \mathrm{Q}_{1}$ so that the potential energy of the system is zero ?
Marking-scheme solution
Nature of \(\displaystyle \mathrm{Q}_{1}\) Value of \(\displaystyle \mathrm{Q}_{1}\)
Nature of \(\displaystyle \mathrm{Q}_{1}\) will be negative. Let, \(\displaystyle \mathrm{Q}_{1}=\mathrm{Q}_{3}=\mathrm{q}\)
\[\begin{aligned}
& \frac{1}{4 \pi \varepsilon_{0}}\left[\frac{\mathrm{q} \mathrm{Q}_{2}}{\mathrm{d}}+\frac{\mathrm{q} \mathrm{q}}{2 \mathrm{d}}+\frac{\mathrm{Q}_{2} \mathrm{q}}{\mathrm{d}}\right]=0 \\
& \frac{1}{4 \pi \varepsilon_{0} \mathrm{d}}\left[\mathrm{q} \mathrm{Q}_{2}+\frac{\mathrm{q}^{2}}{2}+\mathrm{Q}_{2} \mathrm{q}\right]=0 \\
& 2 \mathrm{q} \mathrm{Q}_{2}+\frac{\mathrm{q}^{2}}{2}=0 \\
& 2 \mathrm{q} \mathrm{Q}_{2}=-\frac{\mathrm{q}^{2}}{2} \\
& \mathrm{Q}_{1}=\mathrm{q}=-4 \mathrm{Q}_{2}
\end{aligned}
\]
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