CBSE 2026 · Region 5 · Set 1 · Q32 · 5 marks
(i)A rectangular loop of sides a and b carrying current I is placed in a magnetic field $\displaystyle \overrightarrow{\mathrm{B}}$ such that its area vector $\displaystyle \overrightarrow{\mathrm{A}}$ makes an angle $\displaystyle \theta$ with $\displaystyle \overrightarrow{\mathrm{B}}$. With the help of a suitable diagram, show that the torque $\displaystyle \vec{\tau}$ acting on the loop is given by $\displaystyle \vec{\tau}=\vec{\mathrm{m}} \times \vec{\mathrm{B}}$, where $\displaystyle \vec{\mathrm{m}}(=\mathrm{I} \vec{\mathrm{A}})$ is the magnetic dipole moment of the loop.(ii)A circular coil of $\displaystyle 100$ turns and radius $\displaystyle \left(\frac{10}{\sqrt{\pi}}\right) \mathrm{cm}$ carrying current of $\displaystyle 5 \cdot 0 \mathrm{~A}$ is suspended vertically in a uniform horizontal magnetic field of $\displaystyle 2.0$ T. The field makes an angle $\displaystyle 30$° with the normal to the coil. Calculate :(I)the magnetic dipole moment of the coil, and(II)the magnitude of the counter torque that must be applied to prevent the coil from turning.(i)Derive an expression for the force $\displaystyle \overrightarrow{\mathrm{F}}$ acting on a conductor of length L and area of cross-section A carrying current I and placed in a magnetic field $\displaystyle \overrightarrow{\mathrm{B}}$.(ii)A part of a wire carrying $\displaystyle 2.0$ A current and bent at $\displaystyle 90$° at two points is placed in a region of uniform magnetic field $\displaystyle \overrightarrow{\mathrm{B}}=-(0.50 \mathrm{~T}) \hat{\mathrm{k}}$, as shown in the figure. Calculate the magnitude of the net force acting on the wire.
(i)
A rectangular loop of sides a and b carrying current I is placed in a magnetic field $\displaystyle \overrightarrow{\mathrm{B}}$ such that its area vector $\displaystyle \overrightarrow{\mathrm{A}}$ makes an angle $\displaystyle \theta$ with $\displaystyle \overrightarrow{\mathrm{B}}$. With the help of a suitable diagram, show that the torque $\displaystyle \vec{\tau}$ acting on the loop is given by $\displaystyle \vec{\tau}=\vec{\mathrm{m}} \times \vec{\mathrm{B}}$, where $\displaystyle \vec{\mathrm{m}}(=\mathrm{I} \vec{\mathrm{A}})$ is the magnetic dipole moment of the loop.
(ii)
A circular coil of $\displaystyle 100$ turns and radius $\displaystyle \left(\frac{10}{\sqrt{\pi}}\right) \mathrm{cm}$ carrying current of $\displaystyle 5 \cdot 0 \mathrm{~A}$ is suspended vertically in a uniform horizontal magnetic field of $\displaystyle 2.0$ T. The field makes an angle $\displaystyle 30$° with the normal to the coil. Calculate :
(I)
the magnetic dipole moment of the coil, and
(II)
the magnitude of the counter torque that must be applied to prevent the coil from turning.
(i)
Derive an expression for the force $\displaystyle \overrightarrow{\mathrm{F}}$ acting on a conductor of length L and area of cross-section A carrying current I and placed in a magnetic field $\displaystyle \overrightarrow{\mathrm{B}}$.
(ii)
A part of a wire carrying $\displaystyle 2.0$ A current and bent at $\displaystyle 90$° at two points is placed in a region of uniform magnetic field $\displaystyle \overrightarrow{\mathrm{B}}=-(0.50 \mathrm{~T}) \hat{\mathrm{k}}$, as shown in the figure. Calculate the magnitude of the net force acting on the wire.
Marking-scheme solution
(i)
(a)
(b)
According to Right Hand Screw Rule,
Forces on BC & DA are equal and opposite in direction with same line of action, hence they cancel out each other.
Force on arm AB & CD, are also equal and opposite in direction but there is a difference in line of action so, a torque will act on it.
\[\mathrm{F}_{1}=\mathrm{F}_{2}=\mathrm{Ib} \mathrm{~B}
\]
$\displaystyle \tau=$ Force x perpendicular distance
\[\begin{aligned}
& \tau=\mathrm{F}_{1}(\mathrm{a} / 2) \sin \theta+\mathrm{F}_{2}(\mathrm{a} / 2) \sin \theta \\
&=(\mathrm{IbB}) \mathrm{a} \sin \theta \\
& \tau=\mathrm{IAB} \sin \theta \\
& \overrightarrow{\mathrm{~m}}=\mathrm{I} \overrightarrow{\mathrm{~A}} \\
& \tau=\mathrm{mB} \sin \theta \\
& \vec{\tau}=\overrightarrow{\mathrm{m}} \times \overrightarrow{\mathrm{B}}
\end{aligned}
\]
Moving Charges and MagnetismTorque on Current Loop, Magnetic DipoleApplylong_answerhard
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CBSE Class 12 Physics past-paper question from the 2026board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.