CBSE 2026 · Region 3 · Set 3 · Q5 · 1 mark

An electric dipole with dipole moment $\displaystyle \overrightarrow{\mathrm{P}}=\left(2 \cdot 54 \times 10^{-28} \mathrm{C} . \mathrm{m}\right)(2 \cdot 00 \hat{\mathrm{i}}+3 \cdot 00 \hat{\mathrm{j}})$ is placed in an electric field $\displaystyle \overrightarrow{\mathrm{E}}=\left(1000 \frac{\mathrm{~N}}{\mathrm{C}}\right) \hat{\mathrm{i}}$. An external agent turns the dipole until its electric dipole moment is $\displaystyle \overrightarrow{\mathrm{P}}=\left(2 \cdot 54 \times 10^{-28} \mathrm{C} . \mathrm{m}\right)(-3 \cdot 00 \hat{\mathrm{i}}+2 \cdot 00 \hat{\mathrm{j}})$. The work done by the agent is :

CBSE Class 12 Physics past-paper question from the 2026board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.