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CBSE 2024 · Region 5 · Set 2 · Q21 · 2 marks

A proton of energy $\displaystyle 1.6$ MeV approaches a gold nucleus ( $\displaystyle \mathrm{Z}=79$ ). Find the distance of its closest approach.

Electrostatic Potential and CapacitancePotential Energy of a System of ChargesApplyvery_short_answermedium

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