CBSE 2026 · Region 4 · Set 2 · Q29 · 3 marks
Solve the following Linear Programming Problem graphically : Minimize $\displaystyle \mathrm{Z}=20 \mathrm{x}+10 \mathrm{y}$ subject to \[\begin{array}{r} \mathrm{x}+2 \mathrm{y} \leq 40 \\ 3 \mathrm{x}+\mathrm{y} \geq 30 \\ 4 \mathrm{x}+3 \mathrm{y} \geq 60 \\ \mathrm{x}, \mathrm{y} \geq 0 \end{array} \]
Marking-scheme solution
| Corner point | Value of Z = 20x + 10y |
| A $\displaystyle (40, 0)$ | $\displaystyle 800$ |
| B $\displaystyle (15, 0)$ | $\displaystyle 300$ |
| C $\displaystyle (6, 12)$ | $\displaystyle 240$ |
| D $\displaystyle (4, 18)$ | $\displaystyle 260$ |
Linear ProgrammingLinear Programming Problem and its Mathematical FormulationApplynumericmedium
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CBSE Class 12 Mathematics past-paper question from the 2026board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.