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Mathematics · 2026 · 3 marks
CBSE 2026 · Region 4 · Set 2 · Q29
Solve the following Linear Programming Problem graphically: Minimize Z =20 x +10 y subject to x +2 y ≤ 40; 3 x + y ≥ 30; 4 x +3 y ≥ 60; x, y ≥ 0
Solve the following Linear Programming Problem graphically : Minimize $\displaystyle \mathrm{Z}=20 \mathrm{x}+10 \mathrm{y}$ subject to \[\begin{array}{r} \mathrm{x}+2 \mathrm{y} \leq 40 \\ 3 \mathrm{x}+\mathrm{y} \geq 30 \\ 4 \mathrm{x}+3 \mathrm{y} \geq 60 \\ \mathrm{x}, \mathrm{y} \geq 0 \end{array} \]
Marking-scheme solution
| Corner point | Value of Z = 20x + 10y |
| A $\displaystyle (40, 0)$ | $\displaystyle 800$ |
| B $\displaystyle (15, 0)$ | $\displaystyle 300$ |
| C $\displaystyle (6, 12)$ | $\displaystyle 240$ |
| D $\displaystyle (4, 18)$ | $\displaystyle 260$ |
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CBSE Class 12 Mathematics past-paper question from the 2026 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.