CBSE 2026 · Region 4 · Set 3 · Q29 · 3 marks
Solve the following Linear Programming Problem graphically : \[\text { Maximize } \mathrm{Z}=20 \mathrm{x}+10 \mathrm{y} \] subject to constraints \[\begin{aligned} \mathrm{x}+2 \mathrm{y} & \leq 28 \\ 3 \mathrm{x}+\mathrm{y} & \leq 24 \\ \mathrm{x} & \geq 2 \\ \mathrm{x}, \mathrm{y} & \geq 0 \end{aligned} \]
Marking-scheme solution
| Corner point | Value of $\displaystyle Z = 20x + 10y$ |
| A $\displaystyle (2, 0)$ | $\displaystyle 40$ |
| B $\displaystyle (8, 0)$ | $\displaystyle 160$ |
| C $\displaystyle (4, 12)$ | $\displaystyle 200$ |
| D $\displaystyle (2, 13)$ | $\displaystyle 170$ |
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CBSE Class 12 Mathematics past-paper question from the 2026board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.