CBSE 2026 · Region 5 · Set 1 · Q29 · 3 marks
Solve the following Linear Programming Problem graphically : Maximize $\displaystyle \mathrm{Z}=\frac{2 \mathrm{x}}{5}+\frac{3 \mathrm{y}}{10}$ subject to constraints \[\begin{array}{r} 2 \mathrm{x}+\mathrm{y} \leq 1000 \\ \mathrm{x}+\mathrm{y} \leq 800 \\ \mathrm{x}, \mathrm{y} \geq 0 . \end{array} \]
Marking-scheme solution
| Corner Points | Value of Z |
| $\displaystyle (0, 0)$ | $\displaystyle 0$ |
| $\displaystyle (500, 0)$ | $\displaystyle 200$ |
| $\displaystyle (200, 600)$ | $\displaystyle 260 $ |
| $\displaystyle (0, 800)$ | $\displaystyle 240$ |
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CBSE Class 12 Mathematics past-paper question from the 2026board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.