CBSE 2024 · Region 5 · Set 2 · Q35 · 5 marks
Solve the following Linear Programming problem graphically : Maximise $\displaystyle \mathrm{Z}=300 \mathrm{x}+600 \mathrm{y}$ Subject to $\displaystyle \mathrm{x}+2 \mathrm{y} \leq 12$ \[\begin{aligned} & 2 \mathrm{x}+\mathrm{y} \leq 12 \\ & \mathrm{x}+\frac{5}{4} \mathrm{y} \geq 5 \\ & \mathrm{x} \geq 0, \mathrm{y} \geq 0 \end{aligned} \]
Marking-scheme solution
| Corner Points | Value of $\displaystyle Z = 300x + 600y$ |
| $\displaystyle A(0,4)$ | $\displaystyle Z = 2400$ |
| $\displaystyle B(0,6)$ | $\displaystyle Z = 3600$ |
| $\displaystyle C(4,4)$ | $\displaystyle Z = 3600$ |
| $\displaystyle D(6,0)$ | $\displaystyle Z = 1800$ |
| $\displaystyle E(5,0)$ | $\displaystyle Z = 1500$ |
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