CBSE 2024 · Region 5 · Set 3 · Q35 · 5 marks
Solve the following L.P.P. graphically : Minimise $\displaystyle \mathrm{Z}=6 \mathrm{x}+3 \mathrm{y}$ Subject to constraints \[\begin{aligned} & 4 \mathrm{x}+\mathrm{y} \geq 80 \\ & \mathrm{x}+5 \mathrm{y} \geq 115 \\ & 3 \mathrm{x}+2 \mathrm{y} \leq 150 \\ & \mathrm{x}, \mathrm{y} \geq 0 \end{aligned} \]
Marking-scheme solution
| Corner Points | Value of $\displaystyle \mathrm{Z}=6 \mathrm{x}+3 \mathrm{y}$ |
| $\displaystyle A(2,72)$ | $\displaystyle \mathrm{Z}=228$ |
| $\displaystyle B(15,20)$ | $\displaystyle \mathrm{Z}=150$ |
| $\displaystyle C(40,15)$ | $\displaystyle \mathrm{Z}=285$ |
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CBSE Class 12 Mathematics past-paper question from the 2024board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.