CBSE 2024 · Region 5 · Set 1 · Q35 · 5 marks
Solve the following L.P.P. graphically : Maximise $\displaystyle \mathrm{Z}=60 \mathrm{x}+40 \mathrm{y}$ Subject to $\displaystyle \mathrm{x}+2 \mathrm{y} \leq 12$ \[\begin{aligned} & 2 \mathrm{x}+\mathrm{y} \leq 12 \\ & 4 \mathrm{x}+5 \mathrm{y} \geq 20 \\ & \mathrm{x}, \mathrm{y} \geq 0 \end{aligned} \]
Marking-scheme solution
| Corner Points | Value of $\displaystyle Z = 60x + 40y$ |
| $\displaystyle A(0,4)$ | $\displaystyle Z = 160$ |
| $\displaystyle B(0,6)$ | $\displaystyle Z = 240$ |
| $\displaystyle C(4,4)$ | $\displaystyle Z = 400$ |
| $\displaystyle D(6,0)$ | $\displaystyle Z = 360$ |
| $\displaystyle E(5,0)$ | $\displaystyle Z = 300$ |
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CBSE Class 12 Mathematics past-paper question from the 2024board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.