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Mathematics · 2023 · 1 mark

CBSE 2023 · Region 3 · Set 3 · Q16

∫ e^- x ((x +1)/(x^2)) dx is equal to:

$\displaystyle \int \mathrm{e}^{-\mathrm{x}}\left(\frac{\mathrm{x}+1}{\mathrm{x}^{2}}\right) \mathrm{dx}$ is equal to :

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