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Mathematics · 2025 · 1 mark
CBSE 2025 · Region 7 · Set 3 · Q14
∫ (e^- x)/(16+9 e^-2 x) dx is equal to:
$\displaystyle \int \frac{\mathrm{e}^{-\mathrm{x}}}{16+9 \mathrm{e}^{-2 \mathrm{x}}} \mathrm{dx}$ is equal to :
Official answer
(B)
$\displaystyle -\frac{1}{12} \tan ^{-1}\left(\frac{3 \mathrm{e}^{-\mathrm{x}}}{4}\right)+\mathrm{C}$
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CBSE Class 12 Mathematics past-paper question from the 2025 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.