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Mathematics · 2026 · 1 mark
CBSE 2026 · Region 4 · Set 1 · Q10
If ∫_0^1 dx/(e^x + e^- x)= tan^-1 e + k, then the value of k is:
If $\displaystyle \int_{0}^{1} \frac{\mathrm{dx}}{\mathrm{e}^{\mathrm{x}}+\mathrm{e}^{-\mathrm{x}}}=\tan ^{-1} \mathrm{e}+\mathrm{k}$, then the value of k is :
Official answer
(D)
$\displaystyle -\frac{\pi}{4}$
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CBSE Class 12 Mathematics past-paper question from the 2026 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.