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Mathematics · 2026 · 1 mark
CBSE 2026 · Region 5 · Set 3 · Q11
If ∫_0^1(6 x^2-4 x + k ) dx =0, then the value of k is:
If $\displaystyle \int_{0}^{1}\left(6 \mathrm{x}^{2}-4 \mathrm{x}+\mathrm{k}\right) \mathrm{dx}=0$, then the value of k is :
Official answer
(B)
$\displaystyle 0$
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CBSE Class 12 Mathematics past-paper question from the 2026 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.