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CBSE 2025 · Region 1 · Set 3 · Q3 · 1 mark

If $\displaystyle \int_{0}^{1} \frac{\mathrm{e}^{x}}{1+x} \mathrm{~d} x=\alpha$, then $\displaystyle \int_{0}^{1} \frac{\mathrm{e}^{x}}{(1+x)^{2}} \mathrm{~d} x$ is equal to

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