CBSE 2023 · Region 1 · Set 2 · Q25 · 2 marks
For two non-zero vectors $\displaystyle \vec{\mathrm{a}}$ and $\displaystyle \vec{\mathrm{b}}$, if $\displaystyle |\vec{\mathrm{a}}-\vec{\mathrm{b}}|=|\vec{\mathrm{a}}+\vec{\mathrm{b}}|$, then find the angle between $\displaystyle \overrightarrow{\mathrm{a}}$ and $\displaystyle \overrightarrow{\mathrm{b}}$.
Marking-scheme solution
$$\begin{aligned}
& |\vec{\mathrm{a}}-\vec{\mathrm{b}}|^{2}=|\vec{\mathrm{a}}+\vec{\mathrm{b}}|^{2} \\
& \Rightarrow|\vec{\mathrm{a}}|^{2}-2 \vec{\mathrm{a}} \cdot \vec{\mathrm{b}}+|\vec{\mathrm{b}}|^{2}=|\vec{\mathrm{a}}|^{2}+2 \vec{\mathrm{a}} \cdot \vec{\mathrm{b}}+|\vec{\mathrm{b}}|^{2} \\
& \Rightarrow 4 \vec{\mathrm{a}} \cdot \vec{\mathrm{b}}=0 \\
& \Rightarrow \text { angle between } \overrightarrow{\mathrm{a}} \text { and } \overrightarrow{\mathrm{b}} \text { is } 90^{\circ}
\end{aligned}
$$
Vector AlgebraProduct of Two VectorsApplyvery_short_answereasy
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CBSE Class 12 Mathematics past-paper question from the 2023board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.