CBSE 2025 · Region 7 · Set 1 · Q36 · 4 marks
Three friends $\displaystyle \mathrm{A}, \mathrm{B}$ and C move out from the same location O at the same time in three different directions to reach their destinations. They move out on straight paths and decide that A and B after reaching their destinations will meet up with C at his predecided destination, following straight paths from $\displaystyle \mathrm{A}$ to $\displaystyle C$ and $\displaystyle \mathrm{B}$ to $\displaystyle C$ in such a way that $\displaystyle \overrightarrow{O \mathrm{A}}=\vec{\mathrm{a}}$, $\displaystyle \overrightarrow{\mathrm{OB}}=\overrightarrow{\mathrm{b}}$ and $\displaystyle \overrightarrow{\mathrm{OC}}=5 \overrightarrow{\mathrm{a}}-2 \overrightarrow{\mathrm{~b}}$ respectively.
Based upon the above information, answer the following questions :(i)Complete the given figure to explain their entire movement plan along the respective vectors. Case Study - $\displaystyle 2$
Three friends $\displaystyle \mathrm{A}, \mathrm{B}$ and C move out from the same location O at the same time in three different directions to reach their destinations. They move out on straight paths and decide that A and B after reaching their destinations will meet up with C at his predecided destination, following straight paths from $\displaystyle \mathrm{A}$ to $\displaystyle C$ and $\displaystyle \mathrm{B}$ to $\displaystyle C$ in such a way that $\displaystyle \overrightarrow{O \mathrm{A}}=\vec{\mathrm{a}}$, $\displaystyle \overrightarrow{\mathrm{OB}}=\overrightarrow{\mathrm{b}}$ and $\displaystyle \overrightarrow{\mathrm{OC}}=5 \overrightarrow{\mathrm{a}}-2 \overrightarrow{\mathrm{~b}}$ respectively.
Based upon the above information, answer the following questions :
(i)
Complete the given figure to explain their entire movement plan along the respective vectors. Case Study - $\displaystyle 2$
Marking-scheme solution
(i) The Complete figure of their entire movement plan is:
(ii) \(\displaystyle \overrightarrow{\mathbf{A C}}=\overrightarrow{\mathbf{O C}}-\overrightarrow{\mathbf{O A}}=\mathbf{4} \overrightarrow{\mathbf{a}}-\mathbf{2 b}, \overrightarrow{\mathbf{B C}}=\overrightarrow{\mathbf{O C}}-\overrightarrow{\mathbf{O B}}=\mathbf{5} \overrightarrow{\mathbf{a}}-\mathbf{3} \overrightarrow{\mathbf{b}}\)
(iii) (a) we are given:
\[\begin{array}{r}
\theta=\cos ^{-1}\left(\frac{\overrightarrow{\mathbf{a}} \cdot \overrightarrow{\mathbf{b}}}{|\overrightarrow{\mathbf{a}}||\overrightarrow{\mathbf{b}}|}\right)=\cos ^{-1} \frac{1}{1 \times 2}=\cos ^{-1} \frac{1}{2} \\
|\overrightarrow{\mathbf{a}} \times \overrightarrow{\mathbf{b}}|=|\overrightarrow{\mathbf{a}}||\overrightarrow{\mathbf{b}}| \sin \theta=1(2) \frac{\sqrt{3}}{2}=\sqrt{3}
\end{array}
\]
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CBSE Class 12 Mathematics past-paper question from the 2025board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.