✓ Board-verified
Mathematics · 2023 · 3 marks
CBSE 2023 · Region 1 · Set 1 · Q31
(a) Evaluate: ∫_0^((π)/2) e^x sin x d x
(a)
Evaluate : \[\int_{0}^{\frac{\pi}{2}} \mathrm{e}^{\mathrm{x}} \sin \mathrm{x} d \mathrm{x} \]
OR
(b)
Find : \[\int \frac{1}{\cos (\mathrm{x}-\mathrm{a}) \cos (\mathrm{x}-\mathrm{b})} d \mathrm{x} \]
Marking-scheme solution
(a)
Let $\displaystyle \mathrm{I}=\int \mathrm{e}^{\mathrm{x}} \sin \mathrm{x} \mathrm{dx}$
$$=\mathrm{e}^{\mathrm{x}} \sin \mathrm{x}-\int \cos \mathrm{xe}^{\mathrm{x}} \mathrm{dx}
OR
(b)
Let $\displaystyle \mathrm{I}=\int \frac{1}{\cos (\mathrm{x}-\mathrm{a}) \cos (\mathrm{x}-\mathrm{b})} \mathrm{dx}$
$$=\frac{1}{\sin (\mathrm{a}-\mathrm{b})} \int \frac{\sin [(\mathrm{x}-\mathrm{b})-(\mathrm{x}-\mathrm{a})]}{\cos (\mathrm{x}-\mathrm{a}) \cos (\mathrm{x}-\mathrm{b})} \mathrm{dx}
More from Integrals
- Evaluate: ∫_0^π x/(1+ sin x) d x2022 · asked 2×
- Evaluate ∫_-1^1|x^4-x| d x. OR Find ∫ (sin^-1 x)/((1-x^2)^3 / 2) d x.2023
- Find: ∫ (x^2)/((x^2+4)(x^2+9)) d x2023
- Evaluate: ∫_0^π (sin^2026 x)/(sin^2026 x+ cos^2026 x) d x2026
- Evaluate: ∫_1^3 (√x)/(√x+√(4-x)) dx2022
- Find: ∫ ((3 cos x-2) sin x)/(5- sin^2 x-4 cos x) d x OR Evaluate: ∫_-2^2 (x^3+|x|+1)/(x^2+4|x|+4) d x2024
- ∫ (x+5)/((x+6)^2) e^x dx is equal to:2025
- Evaluate ∫ 1/((e^x+e^-x)(e^x-e^-x)) d x log √22023
CBSE Class 12 Mathematics past-paper question from the 2023 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.