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Mathematics · 2023 · 3 marks
CBSE 2023 · Region 4 · Set 3 · Q27
(a) Evaluate: ∫_1 / 3^1 (( x - x^3)^1 / 3)/(x^4) d x
(a)
Evaluate : \[\int_{1 / 3}^{1} \frac{\left(\mathrm{x}-\mathrm{x}^{3}\right)^{1 / 3}}{\mathrm{x}^{4}} d \mathrm{x} \]
OR
(b)
Evaluate : \[\int_{1}^{3}\{|(\mathrm{x}-1)|+|(\mathrm{x}-2)|\} \mathrm{dx} \]
Marking-scheme solution
(a)
$\displaystyle \mathrm{I}=\int_{1 / 3}^{1} \frac{\left(\mathrm{x}-\mathrm{x}^{3}\right)^{\frac{1}{3}}}{\mathrm{x}^{4}} d \mathrm{x}$
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CBSE Class 12 Mathematics past-paper question from the 2023 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.