CBSE 2022 · Region 3 · Set 3 · Q10 · 3 marks
Evaluate : $\displaystyle \int_{\frac{-\pi}{2}}^{\frac{\pi}{2}}(\sin |x|+\cos |x|) \mathrm{d} x$
Marking-scheme solution
\[\begin{aligned}
& I=\int_{-\pi / 2}^{\pi / 2}(\sin |x|+\cos |x|) d x \\
& f(x)=\sin |x|+\cos |x|
\end{aligned}
\]
= $\displaystyle 4$
IntegralsSome Properties of Definite IntegralsApplyshort_answermedium
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CBSE Class 12 Mathematics past-paper question from the 2022board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.