CBSE 2024 · Region 2 · Set 3 · Q12 · 1 mark
Anti-derivative of $\displaystyle \sqrt{1+\sin 2 \mathrm{x}}, \mathrm{x} \in\left[0, \frac{\pi}{4}\right]$ is :
Official answer
From CBSE’s own marking scheme for this paper.
(B)
$\displaystyle -\cos \mathrm{x}+\sin \mathrm{x}$
IntegralsMethods of IntegrationApplymcqmedium
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CBSE Class 12 Mathematics past-paper question from the 2024board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.